Marquee Structure

Richard Just shared this question 12 days ago
Need Answer

We have a new 6x18 framed marquee made up of 6x3 bays. So the options are: 6x3, 6x6, 6x9, 6x12, 6x15 & 6x18.

If we add these as parent/child type inventory items, could you confirm the correct structure?

6x18 is the parent as it's the largest but if the others are all only assigned a single letter, they don't seem to work with the inventory count ie. a 6x15 still shows as available when a 6x3 is booked (when it shouldn't). It works when you check 6x18 (as it's the parent)

So ATM, we have:

6x3 = A, 6x6 = B, 6x9 = C, 6x12 = D, 6x15 = E, 6x18 = A,B,C,D,E

Comments (3)

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If the 6x6, 6x9, 6x12, 6x15, and 6x18 are all made up of 6x3's then I would have 6x3 = A and then do 6x6=A,A; 6x9=A,A,A; 6x12=A,A,A,A; 6x15=A,A,A,A,A; and 6x18=A,A,A,A,A,A. This would still allow one 6x3 available when the 6x15 is booked, does the 6x15 have a piece that would cause the 6x3 to be overbooked? I'm having trouble finding these items in you account what is the name of the parent?

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Can you give us both scenarios?


Ie. They were able to be booked with varying quantities? Ie. We could hire a 6x3 even when another variation was booked?


And then also if they ALL become unavailable when any one piece is booked?


We made them inactive until we figured it out. They are under "marquees and shade"

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If you have 6 of the 6x3 tents then the system would know you have 3 of the 6x6 tents, 2 of the 6x9 tents and 1 of the 6x15/6x18 tents. This would also mean that is 6x9 is booked then 1 of the 6x6 tents would be available and 3 of the 6x3 tents would be available. In the A,B,C,D,E scenario the 6x3 ,6x6, 6x9, 6x12, 6x15 would not be related to each other.

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